16x^2=32x-16

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Solution for 16x^2=32x-16 equation: 



16x^2=32x-16

We move all terms to the left:

16x^2-(32x-16)=0

We get rid of parentheses

16x^2-32x+16=0

a = 16; b = -32; c = +16;
Δ = b2-4ac
Δ = -322-4·16·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{32}{32}=1$

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